I wanted to confirm that I solved these problems correctly (we had to convert the polar curves to Cartesian equations). 1.rcos(theta)=1 x=1 2.r=2*sin(theta)+2*cos(theta) r^2=2rsin(theta)+2rcos(theta) x^2+y^2=2y+2x (a little unsure
I have no idea how to do these type of problems. -------Problem-------- Solve each equation on the interval 0 less than or equal to theta less than 2 pi 42. SQRT(3) sin theta + cos theta = 1 ---------------------- There is an
Please help me with these problems. Work and answer is appreciated! :) thanks. 1. Find on the interval theta is greater than or equal to 0 and less than 2pi; then find the general solution: 5tantheta+1=-2.89 16cos^2theta-6=3
For the equation 4 cos theta - sqrt12 =0, where 0< theta < or equal 2pi determine the measure of theta. One answer I got was 2pi/3, 4pi/3 and another time it totally different 5 pi/6, 7pi/6. Are either of these right if not HELP!