urgent math
without graphing, find the vertex, the azis of symemtry, and the maximum value or the minium value.
asked by
Anne

sorry i forgot to put the problem. here it is:
f(x)=4(x+5)^26posted by Anne

yk = a(xh)^2
has vertex at (h,k).
Naturally, the max/min is at the vertex and the vertex is on the axis of symmetry.posted by Steve
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