without graphing, find the vertex, the azis of symemtry, and the maximum value or the minium value.
sorry i forgot to put the problem. here it is:
f(x)=4(x+5)^2-6posted by Anne
y-k = a(x-h)^2
has vertex at (h,k).
Naturally, the max/min is at the vertex and the vertex is on the axis of symmetry.posted by Steve