Note that pi lim arctan(x ) = ---- x -> +oo 2 Now evaluate / pi \ lim |arctan(x ) - -----| x x -> +oo \ 2 / I'm not exactly sure how to attempt it. I have tried h'opital's rule but I don't believe you can use it here. Any help
gahh i cant figure this one out either. you have you verify the identity only using one side of the equation: sec^2x*sin^2x+sec^2x=-1 this identity cannot possible be true. on the left side you are adding 2 squared quantities, how
The question is find the area of the reagion that is bounded by the curve y=arctan x, x=0, x=1, and the x-axis. So I've drawn the enclosed region. To find the area would I use the Disc/shell method? If so the formula that I came
Solve for X. x^2+4x+4=7 (Hint: Factor the left hand side) I got stuck on this one, please help!!!Thanks in advance Take the hint. Factor the left side. (x+2)^2 = 7 Take square root of both sides. x+2 = sq rt 7 etc .
Arrange these in order from least to greatest: arctan(-sqrt3), arctan 0, arctan(1/2) So far I got the first two values, arctan(-sqrt3), and that's 150 degrees. Arctan 0 would be zero degrees. I'll use just one answer for now, but
Okay so I have a question on my assignment that says: You are given that tan(y) = x. Find sin(y)^2. Express your answer in terms of x. I know its derivatives, and I've tried taking the derivatives of both etc, and got them both to