# calculus

Verify the identity:

arctanx + arctan(1/x)=∏/2

using calculus theory.

(Hint: Differentiate the left hand side of the identity)

1. 0
1. Actually, since tan(pi/2-x) = cot(x)
and cot = 1/tan it falls right out.

Or, using the sum of tangents formula,

tan(arctanx + arctan(1/x))
= [tan(arctan(x)) + tan(arctan(1/x))][1 - tan(arctan(x))*tan(arctan(1/x))]

= [x + 1/x]/[1 - x*1/x] = (x + 1/x)/0 = oo

tan pi/2 = oo

posted by Anonymous

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