calculus

derivatives.
f(x)=(1/-7x^12)
f'(2)=?
f'(-1)=?

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  1. d/dx (top/bottom) = (bottom d/x top - top d/dx bottom) / bottom^2
    f(x) = (-1/7) x^-12
    f'(x) = (-1/7) (-12) x^-13
    f'(x) = (12/7) x^-13
    alternatively

    f(x) = (-1/7) (1/x^12)

    f'(x) = (-1/7) (x^12 * 0 - 1*12*x^11)/x^24

    = (-1/7) (-12 / x^13)

    = 12/(7 x^13) which is (12/7) x^-13
    Now
    substitute 2 for x
    and
    substitute -1 for x

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