If a force of 15.0 N directed east acts on a stationary 5.00 kg mass, what are its acceleration, displacement, and velocity after 10.0 s?
See previous post for solution.
a football is thrown 6.3 feet off the ground with an initial upward velocity of 25 feet per second.
To find the acceleration, displacement, and velocity of the mass, we can use Newton's second law of motion and the equations of motion.
1. Start by finding the acceleration using Newton's second law:
The force acting on the mass is given as 15.0 N directed east. Since the mass is stationary, there is no other force acting on it. According to Newton's second law (F = ma), we can write:
15.0 N = 5.00 kg * a
Rearranging the equation to solve for acceleration (a):
a = 15.0 N / 5.00 kg
a = 3.00 m/s^2
So, the acceleration of the mass is 3.00 m/s^2.
2. Next, we can find the displacement using the equation of motion:
s = ut + 1/2 * a * t^2
Here, u represents the initial velocity (which is zero since the mass is stationary). Substituting the values:
s = 0 * 10.0 s + 1/2 * 3.00 m/s^2 * (10.0 s)^2
s = 0 + 1/2 * 3.00 m/s^2 * 100.0 s^2
s = 150.0 m
Therefore, the displacement of the mass is 150.0 meters.
3. Lastly, we can find the velocity using another equation of motion:
v = u + at
Again, u is the initial velocity (which is zero). Substituting the values:
v = 0 + 3.00 m/s^2 * 10.0 s
v = 30.0 m/s
Hence, after 10.0 seconds, the velocity of the mass is 30.0 m/s.