Physics
The planet Krypton has a mass of
7.1 × 1023 kg and radius of 3.3 × 106 m.
What is the acceleration of an object in free
fall near the surface of Krypton? The gravita
tional constant is 6.6726 × 10−11 N · m2/kg2.
Answer in units of m/s2
asked by
Sam

Force of gravity=(Gm1m2)/(r squared)
m1g=(Gm1m2)/(r squared)
g=(Gm2)/(r squared)
m2=Krypton's mass=7.1x10^23 kg
r= Krypton's radius=3.3x10^6m
G=6.6726x10^11 (N x m^2)/kg^2
Plug in the numbers. You should get
28.265875m/s^2posted by Ray
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