A sum of money is divided between three women A,B and C in the ration 2:3:5.If B receives £2.40 less than C, how much does each receive?
does not matter anymore i figured it out please just answer my other one x
sum of money is divided between three men A, B and C in the ratio 7:5:1. If B has Ro 240 more than C, how much does A receive?
To solve this problem, we can start by assuming the total amount of money is represented by a variable, let's call it "x".
According to the given ratio, A would receive 2 parts out of the total ratio of 2+3+5=10. So, A would receive (2/10) * x = 0.2x.
Similarly, B would receive 3 parts out of the total ratio. So, B would receive (3/10) * x = 0.3x.
And C would receive 5 parts out of the total ratio. So, C would receive (5/10) * x = 0.5x.
We also know that B receives £2.40 less than C. So, we can set up the equation:
0.3x = 0.5x - £2.40
To solve this equation, we can isolate the variable x:
0.3x - 0.5x = -£2.40
-0.2x = -£2.40
Simplifying further:
x = (-£2.40) / (-0.2)
x = £12
Now, we can substitute this value of x back into the original expressions for A, B, and C:
A = 0.2x = 0.2 * £12 = £2.40
B = 0.3x = 0.3 * £12 = £3.60
C = 0.5x = 0.5 * £12 = £6.00
So, A would receive £2.40, B would receive £3.60, and C would receive £6.00.