A bicycle is supported so that in front wheel does not touch the road.The wheels diameteris 0.65 m.The wheel is spun as a rotation rate of 9.3 revolution per second.Find the speed of a point on the outside
R*w
w is the angular speed in radians per second. In this case, that would be 58.4 rad/s.
R is the radius of the wheel.
Do the multiplication
To find the speed of a point on the outside of the wheel, we can use the formula:
Speed = Circumference × Frequency
First, let's find the circumference of the wheel. The circumference of a circle can be calculated using the formula:
Circumference = π × Diameter
Given that the diameter of the wheel is 0.65 m, we can calculate the circumference as follows:
Circumference = π × 0.65 m
Next, we need to find the frequency of rotation in terms of revolutions per second. Given that the rotation rate is 9.3 revolutions per second, the frequency can be calculated as follows:
Frequency = 9.3 revolutions/second
Now, we can substitute the values into the speed formula:
Speed = Circumference × Frequency
Speed = (π × 0.65 m) × (9.3 revolutions/second)
Finally, we can calculate the speed:
Speed ≈ (3.14 × 0.65 m) × 9.3 revolutions/second
Speed ≈ (2.021 m) × 9.3 revolutions/second
Speed ≈ 18.78 m/s
Therefore, the speed of a point on the outside of the wheel is approximately 18.78 m/s.