# physics

A 83-kg worker clings to a lightweight rope going over a lightweight, low-friction pulley. The other end of the rope is connected to a 66-kg barrel of bricks. If the worker is initially at rest 16 m above the ground, how fast will he or she be moving when he or she hits the ground?

1. Vf^2 = Vo^2 + 2g*d,
Vf^2 = 0 + 19.6*16 = 313.6,
Vf = 17.7m/s.

posted by Henry

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