a car accelerates along a straight road from the rest to 90 km/h in 5 s what is the magnitude of its average acceleration
5sec = 5/3600 hours
change in velicity is 90 km/h in 5/3600 hrs so the acceleration is
90km/h/(5/3600 hr) = 90*3600/5 km/hr^2 = 64800 km/hr^2
Not the units you wanted? Well, I'll let you change from km/hr^2 to m/s^2
Jean baptiste
To find the magnitude of the car's average acceleration, we can use the formula:
average acceleration = change in velocity / time
1. First, convert the initial velocity and final velocity from kilometers per hour (km/h) to meters per second (m/s). We know that 1 km/h is equal to 0.27778 m/s.
Initial velocity, u = 0 km/h = 0 m/s
Final velocity, v = 90 km/h = 90 * 0.27778 m/s = 25 m/s
2. Next, substitute the values of the final velocity and time into the formula:
average acceleration = (v - u) / t
average acceleration = (25 m/s - 0 m/s) / 5 s
3. Simplify the expression:
average acceleration = 25 m/s / 5 s
4. Calculate the average acceleration:
average acceleration = 5 m/s^2
Therefore, the magnitude of the car's average acceleration is 5 m/s^2.
To find the magnitude of the average acceleration of the car, we can use the formula:
Average acceleration = Change in velocity / Change in time
First, we need to convert the initial and final velocities from km/h to m/s, since the formula requires the units to be in the same system.
Given: Initial velocity (u) = 0 km/h (rest)
Final velocity (v) = 90 km/h
Time taken (t) = 5 s
Converting km/h to m/s:
1 km/h = 1000 m/3600 s = 5/18 m/s
So, the initial velocity (u) = 0 km/h = 0 m/s
The final velocity (v) = 90 km/h = (90 * 5/18) m/s = 25 m/s
Now, we can substitute the values into the formula:
Average acceleration = (Change in velocity) / (Change in time)
= (v - u) / t
= (25 - 0) / 5
= 5 m/s²
Therefore, the magnitude of the average acceleration of the car is 5 m/s².