A 26.0 kg block is connected to an empty 1.00 kg bucket by a cord running over a frictionless pulley (Fig. 4-57). The coefficient of static friction between the table and the block is 0.490 and the coefficient of kinetic friction between the table and the block is 0.320. Sand is gradually added to the bucket until the system just begins to move.

Part A of the question asked me to calculate the mass of sand added to the bucket which i determined to be 11.7 kg.
Part B asks the acceleration of the system downward. Can someone help?

To calculate the acceleration of the system downward, we need to consider the forces acting on both the block and the bucket.

First, let's summarize the forces acting on the block:
1. The weight of the block (mg), where m is the mass of the block (26.0 kg) and g is the acceleration due to gravity (9.8 m/s^2).
2. The tension in the cord pulling the block upward.

Now, let's consider the forces acting on the bucket:
1. The weight of the bucket (Mg), where M is the mass of the bucket (1.00 kg) and g is the acceleration due to gravity (9.8 m/s^2).
2. The tension in the cord pulling the bucket downward.

At the point just before the system begins to move, we can assume that the static friction between the block and the table is at its maximum, which is equal to the coefficient of static friction (μs) multiplied by the normal force (Fn).

The normal force (Fn) is equal to the weight of the block, as the block is in contact with the table.

Now, let's analyze the forces for the block:
- The weight of the block (mg) acts downward.
- The tension in the cord pulls upward.

For the bucket:
- The weight of the bucket (Mg) acts downward.
- The tension in the cord pulls downward.

Since the system is just about to move, the forces are at the verge of overpowering the static friction. Therefore, the net force on each object is equal to the force of static friction.

For the block, the net force is:
Net force on the block = Tension in the cord - Force of static friction = Tension in the cord - (μs * Fn)

For the bucket, the net force is:
Net force on the bucket = Force of static friction - Tension in the cord = (μs * Fn) - Tension in the cord

Since the block and the bucket are connected by the same cord, their accelerations must be the same. Let's denote the common acceleration as 'a'.

Using Newton's second law (force = mass * acceleration) for both the block and the bucket, we can set up the following equations:

Equation for the block:
mg - Tension in the cord = (μs * Fn) = μs * (m * g)

Equation for the bucket:
(M * g) - Tension in the cord = (μs * Fn) = μs * (m * g)

Now, substitute Fn with m * g (weight of the block):
mg - Tension in the cord = μs * (m * g)
(M * g) - Tension in the cord = μs * (m * g)

Since we have two unknowns (Tension in the cord and 'a'), we need another equation to solve for them.

To establish a relationship between Tension in the cord and the mass of the sand added to the bucket, we can use the fact that the total mass of the system is constant:
m + M = 26.0 kg + 1.00 kg = 27.00 kg
Since you mentioned that the mass of the sand added to the bucket is 11.7 kg, we know that M = 11.7 kg.

Now, we can rewrite the equations as:
(26.0 kg * g) - Tension in the cord = μs * (26.0 kg * g)
(11.7 kg * g) - Tension in the cord = μs * (26.0 kg * g)

Simplifying these equations:
(26.0 kg * g) - Tension in the cord = (μs * 26.0 kg * g)
(11.7 kg * g) - Tension in the cord = (μs * 26.0 kg * g)

Substitute the known value of μs (0.490):
(26.0 kg * g) - Tension in the cord = (0.490 * 26.0 kg * g)
(11.7 kg * g) - Tension in the cord = (0.490 * 26.0 kg * g)

Now, we have two equations with two unknowns: Tension in the cord and 'a'.

By solving these equations simultaneously, we can find the values of Tension in the cord and 'a'. Once we know the tension, we can use it to calculate the acceleration (a) of the system downward.

Note: I'm assuming that the coefficient of kinetic friction (μk) mentioned in the problem is not relevant to finding the acceleration of the system. Let me know if you should consider μk as well for part B of the question.

To calculate the acceleration of the system downward, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.

In this case, the net force acting on the system is the force of gravity pulling the block downward minus the frictional force. The frictional force is given by:

frictional force = coefficient of kinetic friction * normal force

The normal force is the force exerted by the table on the block and is equal to the weight of the block, which is:

normal force = mass of the block * acceleration due to gravity

Now, let's break down the forces acting on each object separately.

For the block:
- The force of gravity pulling it downward is:
force of gravity on the block = mass of the block * acceleration due to gravity

- The frictional force opposing its motion is given by:
frictional force on the block = coefficient of kinetic friction * normal force

For the bucket:
- The force of gravity pulling it downward is:
force of gravity on the bucket = mass of the bucket * acceleration due to gravity

- The tension in the cord is equal to the force pulling the bucket upward.

Since the tension in the cord is equal to the force of gravity on the bucket, we have:

tension in the cord = force of gravity on the bucket = mass of the bucket * acceleration due to gravity

Since the block and the bucket are connected by the same cord and have the same acceleration, we can write the following equation:

force of gravity on the block - frictional force on the block = tension in the cord

Now, let's substitute the expressions for each force:

mass of the block * acceleration due to gravity - coefficient of kinetic friction * normal force = mass of the bucket * acceleration due to gravity

Substituting the expression for the normal force:

mass of the block * acceleration due to gravity - coefficient of kinetic friction * (mass of the block * acceleration due to gravity) = mass of the bucket * acceleration due to gravity

Now, we can solve for acceleration:

acceleration due to gravity * (mass of the block - coefficient of kinetic friction * mass of the block) = mass of the bucket * acceleration due to gravity

Canceling the acceleration due to gravity:

mass of the block - coefficient of kinetic friction * mass of the block = mass of the bucket

mass of the bucket = (1 - coefficient of kinetic friction) * mass of the block

Plugging in the known values:

mass of the bucket = (1 - 0.320) * 26.0 kg

mass of the bucket = 0.680 * 26.0 kg

mass of the bucket = 17.68 kg

So, the mass of the bucket is 17.68 kg.

Since the block and the bucket are connected by the same cord and have the same acceleration, the acceleration of the system downward is the same as the acceleration of the bucket, which is:

acceleration = acceleration due to gravity * (mass of the block - coefficient of kinetic friction * mass of the block) / mass of the bucket

Plugging in the known values:

acceleration = 9.8 m/s^2 * (26.0 kg - 0.320 * 26.0 kg) / 17.68 kg

acceleration = 9.8 m/s^2 * (26.0 kg - 8.32 kg) / 17.68 kg

acceleration = 9.8 m/s^2 * 17.68 kg / 17.68 kg

acceleration = 9.8 m/s^2

Therefore, the acceleration of the system downward is 9.8 m/s^2.