Name the complexes:
[V(ox)(Cl)3]-
[Cr(F)3(I)(H2O)2]
Write the formula for each of the following coordination compounds.
Diamminetetrahydroxochromte (II) ion
Bisethylenediaminediiodomanganese (IV) ion
I think the name for the first one is oxolatetrichlorovandiumate (IV) ion
The second one is? How do you know which ligand to name first?
The first one for the other is [Cr(NH3)2(OH)4]2-
Ligands are named in alphabetical order except where the di/tri/ etc designates substitution on the ligand (not the number used in the coordination sphere). So for the first one, chloro comes before oxalato and trichlor does not change the order. I would name that one
trichlorooxalatovanadate(IV)
I would name the second one as
diaquatrifluoroiodochromium(IV)
I would write the next two as
[(NH3)2(OH)4Cr(II)]^=
[(en)2I2Mn(IV)]^++
All the rules have changed since I was in school so check these out carefully.
14A w/ Lavelle? :]
my discussion is tomorrow thanks guys ;)
To name the complexes and write their formulas, we need to follow the rules for naming and formula writing of coordination compounds.
1. [V(ox)(Cl)3]-:
To name this complex, we first identify the central metal ion as vanadium (V). The ligands present are oxalate (ox) and chloride (Cl). Since oxalate is a polyatomic anion, we use the suffix "-ate" to indicate this. The oxidation state of vanadium is +4.
Therefore, the name of this complex is oxalatetrichlorovandiumate (IV) ion.
To write the formula, we start with the symbol of the metal ion, V, followed by the symbols of the ligands in alphabetical order, along with their respective number of repetitions as indicated by their prefixes. The oxidation state of the metal ion is indicated as a Roman numeral in parentheses.
So, the formula for this complex is [V(ox)(Cl)3]-.
2. [Cr(F)3(I)(H2O)2]:
To determine the name of this complex, we identify the central metal ion as chromium (Cr). The ligands present include fluoride (F), iodide (I), and water (H2O). In this case, we need to determine the naming order for the ligands.
The general rule for naming order of ligands is to consider them in alphabetical order, except for special cases where certain ligands are considered before others. For example, oxalate (ox) and hydroxide (OH-) are usually considered first. However, in this case, we don't have those ligands.
Since fluoride (F) comes before iodide (I) alphabetically, we name it first. Therefore, we will name the ligands in the order F, I, H2O.
The oxidation state of chromium is +3 since there are three fluoride ligands.
Therefore, the name of this complex is trifluoroiodoaquadichromium (III).
To write the formula, we start with the symbol of the metal ion, Cr, followed by the symbols of the ligands in alphabetical order, along with their respective number of repetitions as indicated by their prefixes. The oxidation state of the metal ion is indicated as a Roman numeral in parentheses.
So, the formula for this complex is [Cr(F)3(I)(H2O)2].
3. Diamminetetrahydroxochromate (II) ion:
The name indicates that the central metal ion is chromium (Cr). The ligands present are ammonia (NH3) and hydroxide (OH-). We also have the oxidation state of the metal ion, which is +2.
Therefore, the name of this complex is diamminetetrahydroxochromate (II) ion.
To write the formula, we start with the symbol of the metal ion, Cr, followed by the symbols of the ligands in alphabetical order, along with their respective number of repetitions as indicated by their prefixes. The oxidation state of the metal ion is indicated as a Roman numeral in parentheses.
So, the formula for this complex is [Cr(NH3)2(OH)4]2-.
4. Bisethylenediaminediiodomanganese (IV) ion:
The name indicates that the central metal ion is manganese (Mn). The ligands present are ethylenediamine (en) and iodide (I). We also have the oxidation state of the metal ion, which is +4.
Therefore, the name of this complex is bisethylenediaminediiodomanganese (IV) ion.
To write the formula, we start with the symbol of the metal ion, Mn, followed by the symbols of the ligands in alphabetical order, along with their respective number of repetitions as indicated by their prefixes. The oxidation state of the metal ion is indicated as a Roman numeral in parentheses.
So, the formula for this complex is [Mn(en)2(I)2]4+.