how many molecules will be in 275 grams of c2h6
Calculate molar mass of C2H6 = 30 g mole
Number of moles is then
275 g/30 g mol^-1 = 9.2 mole
1 mole contains 6.02 x 10^23 molecules (Avogadro's number)
So number of molecules =
6.02 x 10^23 molecules mole^-1 x 9.2 mole =
muja numarical sikhna hai
To determine the number of molecules in 275 grams of C2H6 (ethane), you will need to use the concept of molar mass and Avogadro's number.
1. Start by finding the molar mass of C2H6 (ethane). The molar mass is the sum of the atomic masses of all the elements in the compound. C2H6 contains two carbon atoms (C) and six hydrogen atoms (H).
- Atomic mass of carbon (C) = 12.01 grams/mole
- Atomic mass of hydrogen (H) = 1.01 grams/mole
- Molar mass of C2H6 = (2 * 12.01 g/mol) + (6 * 1.01 g/mol) = 30.07 g/mol
2. Use the molar mass of C2H6 to convert the given mass of 275 grams to moles. This can be done using the formula: Moles = Mass / Molar mass.
- Moles of C2H6 = 275g / 30.07 g/mol ≈ 9.14 moles
3. Since one mole of any substance contains Avogadro's number of molecules, you can calculate the number of molecules by multiplying the number of moles by Avogadro's number.
- Avogadro's number = 6.022 × 10^23 molecules/mol
- Number of molecules = 9.14 moles * (6.022 × 10^23 molecules/mol) ≈ 5.50 × 10^24 molecules
Therefore, there would be approximately 5.50 × 10^24 molecules in 275 grams of C2H6 (ethane).