Question is: What is the algebraic equation to determine when they will meet?
For the following information, I understand 5(x+y) = 3000 for 1st plane & 10(x-y) = 3000 for 2nd plane.
When an airplane flies with a given wind, it can travel 3000 km in 5hrs. When the same airplane flies in the opposite direction against the wind it takes 10hrs to fly the same distance. Find the speed of the plane in still air and the speed of the wind.
Divide your first equation by 5 to get : x+y = 600
Divide your 2nd equation by 10 to get: x-y = 300
add them: 2x = 900
x = 450
sub that back into your new 1st
450 + y = 600
y = 150posted by Reiny