In a titration experiment, 22.00mL of a NaOH solution are required to neutralize 24.02 mL of a 0.1094 M HCL solution. what is the molarity of H+ in the HCL solution? (same as the molarity of HCL)
mL NaOH x M NaOH = mL HCl x M HCl
To find the molarity of H+ in the HCl solution, we need to use the balanced chemical equation for the reaction between NaOH and HCl. The equation is:
NaOH + HCl -> NaCl + H2O
From the equation, we can see that the mole ratio between NaOH and HCl is 1:1. This means that for every 1 mole of NaOH, 1 mole of HCl is required to completely react.
Given that 22.00 mL of NaOH solution is required to neutralize 24.02 mL of HCl solution, we can use this information to calculate the moles of NaOH and HCl in the reaction.
First, calculate the moles of NaOH used:
moles NaOH = volume (in liters) x molarity
moles NaOH = 22.00 mL x (1 L / 1000 mL) x molarity of NaOH solution (unknown)
Then, since the mole ratio is 1:1, the moles of NaOH and HCl are the same.
Now, convert the volume of HCl to liters:
volume HCl = 24.02 mL x (1 L / 1000 mL)
Finally, calculate the molarity of HCl:
molarity HCl = moles HCl / volume HCl (in liters)
Substitute the values into the equation and solve for the molarity of HCl (H+):
molarity HCl = moles NaOH / volume HCl (in liters)