Can someone check my answers for me thank you. I have the equation balanced below.
2H2O + K2SO4 --> H2SO4 + 2KOH
Ionic equation for the reaction between sulfuric acid and potassium hydroxide.
2H+ + SO4^2- + 2K+ + 2OH- --> 2K+ + SO4^2- + 2H2O
Net equation would be:
2H+ + 2OH- + 2H2O
The first equation you have written goes the other direction;i.e., it should be written as 2KOH + H2SO4 ==> 2H2O + K2SO4. The second (ionic equation) is ok and the net equation is ok.
Sure, I can help you check your answers. Let's start with the balanced equation:
2H2O + K2SO4 -> H2SO4 + 2KOH
The balanced equation looks correct. Now let's move on to the ionic equation:
Ionic equation for the reaction between sulfuric acid and potassium hydroxide:
In this equation, we need to break down the compounds into their respective ions. In sulfuric acid (H2SO4), the H2SO4 dissociates into H+ and SO4^2- ions. In potassium hydroxide (KOH), the KOH dissociates into K+ and OH- ions.
So the ionic equation becomes:
2H+ + SO4^2- + 2K+ + 2OH- -> 2K+ + SO4^2- + 2H2O
Now let's simplify this equation to the net ionic equation:
Net equation:
In the net equation, we remove the spectator ions that appear on both sides of the equation. In this case, the spectator ions are K+ and SO4^2-. They do not participate in the actual reaction, so we can remove them.
The net equation becomes:
2H+ + 2OH- -> 2H2O
So, your net equation should be:
2H+ + 2OH- -> 2H2O
I hope that helps! Let me know if you have any other questions.