Hydrochloric acid is usually purchased in concentrated form with a 37.0% HCL concentration by mass and a density of 1.20g/mL. How much of the concentrated stock solution in milliliters should you use to make 2.5L of 0.500M HCL
1.2g/ml x 1000ml x 0.37 / 36.5 = 12.16M
12.16m= 2500ml x 0.5
12.16m = 1250ml
x = 1250ml/12.16
x = 103 ml This is answer.
To find out how much of the concentrated stock solution to use, we can use the equation:
M1 × V1 = M2 × V2
Where:
M1 = initial concentration of the stock solution
V1 = volume of the stock solution to be used
M2 = final concentration of the diluted solution
V2 = final volume of the diluted solution
We need to dilute the stock solution to obtain a final concentration of 0.500M and a final volume of 2.5L. We know that the initial concentration of the stock solution is 37.0%, which can be written as 0.37 in decimal form.
Let's plug these values into the equation to solve for V1:
(0.37) × V1 = (0.500) × (2.5)
Simplifying the equation:
0.37V1 = 1.25
Now, divide both sides of the equation by 0.37 to solve for V1:
V1 = 1.25 / 0.37
V1 ≈ 3.38
Therefore, you should use approximately 3.38 mL of the concentrated stock solution to make 2.5L of 0.500M HCl.
To find out how much of the concentrated stock solution of hydrochloric acid you should use, we can use the formula:
M1V1 = M2V2
Where:
M1 = initial molarity of the concentrated stock solution
V1 = volume of the concentrated stock solution
M2 = final molarity of the diluted solution
V2 = final volume of the diluted solution
Let's plug in the values we know:
M1 = 37.0% HCl concentration by mass
V1 = volume of the concentrated stock solution (which we need to find)
M2 = 0.500M HCl
V2 = 2.5L
First, let's convert the percent concentration to molarity:
37.0% HCl = 37.0g HCl / 100g of solution
Since the density of the solution is 1.20g/mL, we can calculate the volume of 37.0g using the density:
Volume of 37.0g HCl = (37.0g) / (1.20g/mL) = 30.83mL
Now let's plug the values into the formula:
M1V1 = M2V2
(37.0M)(30.83mL) = (0.500M)(2.5L)
To solve for V1, rearrange the equation:
V1 = (M2V2) / M1
V1 = (0.500M)(2.5L) / 37.0M
Now we can calculate V1:
V1 = (0.500M)(2.5L) / 37.0M = 0.0676L = 67.6mL
Therefore, you should use 67.6mL of the concentrated stock solution to make 2.5L of 0.500M HCl solution.
#1, calculate the M of the commercial solution.
1000 mL x 1.20 g/mL x 0.37 = grams HCl/1L
grams/molar mass HCl = ?M since that will be moles/L.
Then Mconcd x ?mL concd = 0.500M x 2,500 mL
Solve for ?mL.