calculate the quantity of heat (cal, J) required to change the temperature of 1500g water from 25C to 75C.

do i have this right
1500 X 4.18J/g C X 50C = 313500

I didn't check the math but the procedure is correct.

Wromg

Yes, you have the right approach to solve the problem. The formula to calculate the quantity of heat required is:

Q = m * c * ΔT

Where:
Q = Quantity of heat (in Joules or calories)
m = Mass of the substance (in grams)
c = Specific heat capacity of the substance (in J/g°C or cal/g°C)
ΔT = Change in temperature (in °C)

In your case, you have:
m = 1500g (mass of water)
c = 4.18 J/g°C (specific heat capacity of water in Joules)
ΔT = 75°C - 25°C = 50°C (change in temperature)

Now, let's plug the values into the formula:

Q = 1500g * 4.18 J/g°C * 50°C
Q = 313500 J

So, the quantity of heat required to change the temperature of 1500g of water from 25°C to 75°C is 313500 Joules.