as 390 g of hot milk cools in a mug, it transfers 30,000 J of heat to the environment. What is the temperature change of milk? The specific heat of milk is 3.9 J/g degree C.
recall that heat absorbed released is given by
Q = mc*(T2 - T1)
where
m = mass (in g)
c = specific heat capacity (in J/g-k)
T = temperature (in C or K)
*note: Q is (+) when heat is absorbed and (-) when heat is released.
we're looking for (T2 - T1) here. substituting,
30000 = 390*3.9*(T2 - T1)
(T2-T1) = 19.72 K
hope this helps~ :)
To determine the temperature change of the milk, we can use the formula:
Heat transferred (Q) = mass (m) x specific heat (c) x temperature change (ΔT)
Given:
Mass of milk (m) = 390 g
Specific heat of milk (c) = 3.9 J/g°C
Heat transferred to the environment (Q) = 30,000 J
Rearranging the formula, we can solve for the temperature change (ΔT):
ΔT = Q / (m x c)
Substituting the given values:
ΔT = 30,000 J / (390 g x 3.9 J/g°C)
Calculating:
ΔT = 30,000 J / 1,521 g°C
ΔT ≈ 19.711 °C (rounded to three decimal places)
The temperature change of the milk is approximately 19.711°C.
To determine the temperature change of milk, we can use the formula:
Q = m * c * ΔT
Where:
Q = heat transferred (in Joules)
m = mass of the milk (in grams)
c = specific heat of the milk (in J/g°C)
ΔT = change in temperature (in °C)
Given:
Q = 30,000 J
m = 390 g
c = 3.9 J/g°C
We can rearrange the formula to solve for ΔT:
ΔT = Q / (m * c)
Substituting the given values:
ΔT = 30,000 J / (390 g * 3.9 J/g°C)
Calculating this expression:
ΔT = 30,000 J / 1,521 g°C
ΔT ≈ 19.71 °C
Therefore, the temperature change of the milk is approximately 19.71 °C.