# Logarithms

How do I solve this using logs? I am having a total math meltdown tonight!

10=2^10/n

Thanks again!

1. 10 = 2^(10/n)
log 10 = log(2^10/n)
1 = 10/n log2
n = 10log2

posted by Reiny
2. OMG!! THANKS!!! I totally kept adding in logs where I shouldn't have!! AWESOME!! Thanks!

posted by Math genius! Urgent!

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