y^2-4y+4/2-6y x 2y+4/3y^2-12
First, find the LCD to cancel out the fraction
Combine Like terms before you multiply them.
can u show the working
i don't now wtf so get over it figer it out
To multiply the expression (y^2-4y+4)/(2-6y) by (2y+4)/(3y^2-12), we can follow these steps:
Step 1: Simplify both expressions individually.
First, let's simplify the numerator of the first expression (y^2-4y+4)/(2-6y):
1. Factor the numerator: (y-2)(y-2).
2. Factor the denominator: 2-6y.
So the first expression simplifies to (y-2)(y-2)/(2-6y).
Next, let's simplify the second expression (2y+4)/(3y^2-12):
1. Factor a 2 out of the numerator: 2(y+2).
2. Factor a 3 out of the denominator: 3(y^2-4).
So the second expression simplifies to 2(y+2)/3(y^2-4).
Step 2: Multiply the simplified expressions.
Multiply (y-2)(y-2)/(2-6y) by 2(y+2)/3(y^2-4):
[(y-2)(y-2)/(2-6y)] * [2(y+2)/3(y^2-4)]
Step 3: Cancel out common factors.
In this case, we can simplify the expression further by canceling out common factors between the numerator and denominator:
[(y-2)(y-2)] / [3(y^2-4)]
Step 4: Expand and simplify if needed.
If you expand the numerator, you'll get y^2 - 4y + 4. The denominator stays the same: 3(y^2-4).
Final answer:
The multiplication of (y^2-4y+4)/(2-6y) and (2y+4)/(3y^2-12) simplifies to:
(y^2 - 4y + 4)/(3(y^2-4))