chemistry 105

Lithium reacts with nitrogen gas according to the following reaction: 6Li(s)+N2(g)-->2LiN(s)
What mass of lithium (in g ) is required to react completely with 59.9 mL of N2 gas at STP?

  1. 👍 2
  2. 👎 1
  3. 👁 6,556
  1. Use the ideal gas law..
    PV=nRT
    and solve for moles of N2

    SO....
    (1.00atm)(.0599L)=n(0.0821L*atm/mol*K)(273K)
    solve for n.

    then use "n" moles of N2 and then set up an conversion factor.

    so....
    ___moles of N2 x( 6mol Li/2mol N2) x (MolarMass Li/1mol of Li)

    Then that gives you your mass of Lithium required to react.
    Hope that helps!

    1. 👍 3
    2. 👎 16
  2. .555 g

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    2. 👎 11
  3. .110

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    2. 👎 2

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