PHYSICS

Consider a spaceship located on the Earth-Moon center line (i.e. a line that intersects the centers of both bodies) such that, at that point, the tugs on the spaceship from each celestial body exactly cancel, leaving the craft literally weightless. Take the distance between the centers of the Earth and Moon to be 3.92E+5 km and the Moon-to-Earth mass ratio to be 1.200E-2. What is the spaceship's distance from the center of the Moon?

  1. 👍 0
  2. 👎 0
  3. 👁 72
asked by Courtney hey damon can i get the quadratic on this

  1. you don't need the q

    Let M1 = moon mass; M2 = Earth mass,
    r = distance from spaceraft to moon, and
    D = Earth-moon distance

    When the two gravity pulls are equal,

    M1/r^2 = M2/(D-r)^2
    [(D-r)/r]^2 = M2/M1 = 1/(0.012)
    (D-r)/r = 9.13 = R/r -1
    D/r = 10.13
    Look up D and compute r.

    1. 👍 0
    2. 👎 0
    posted by drwls

Respond to this Question

First Name

Your Response

Similar Questions

  1. physics hey damon one more please! =]

    Consider a spaceship located on the Earth-Moon center line (i.e. a line that intersects the centers of both bodies) such that, at that point, the tugs on the spaceship from each celestial body exactly cancel, leaving the craft

    asked by Jon on January 14, 2008

  2. physics

    still cant get this one? so damon i know you wanna help! or anyone else im open for suggestions haha Consider a spaceship located on the Earth-Moon center line (i.e. a line that intersects the centers of both bodies) such that, at

    asked by rory on December 21, 2007

  3. Physics

    Consider a spaceship located on the Earth-Moon center line (i.e. a line that intersects the centers of both bodies) such that, at that point, the tugs on the spaceship from each celestial body exactly cancel, leaving the craft

    asked by Lindsay on December 16, 2007

  4. Physics

    Consider a spaceship located on the Earth-Moon center line (i.e. a line that intersects the centers of both bodies) such that, at that point, the tugs on the spaceship from each celestial body exactly cancel, leaving the craft

    asked by Lindsay on December 17, 2007

  5. Physics

    I still cannot solve this problem: Consider a spaceship located on the Earth-Moon center line (i.e. a line that intersects the centers of both bodies) such that, at that point, the tugs on the spaceship from each celestial body

    asked by Lindsay on December 17, 2007

  6. PHYSICSS!!!

    still cant get this one? so damon i know you wanna help! or anyone else im open for suggestions haha Consider a spaceship located on the Earth-Moon center line (i.e. a line that intersects the centers of both bodies) such that, at

    asked by Rory still need help damon and others on December 26, 2007

  7. Calculus Physics

    Imagine a spaceship on its way to the moon from the earth. Find the point, as measured from the center of the earth, where the force of gravity due to the earth is balanced exactly by the gravity of the moon. This point lies on a

    asked by danny on March 2, 2015

  8. Physics

    A spaceship of mass 175,000 kg travels from the Earth to the Moon along a line that passes through the center of the Earth and the center of the Moon. At what distance from the center of the Earth is the force due to the Earth

    asked by Meder on February 24, 2013

  9. physics

    magine a straight line connecting the centers of the earth and the moon. At some point along this line the gravitational forces pulling a spacecraft towards the moon and towards the earth exactly balance each other, and the craft

    asked by peter on March 20, 2011

  10. physics

    A spaceship of mass m travels from the Earth to the Moon along a line that passes through the center of the Earth and the center of the Moon. (a) At what distance from the center of the Earth is the force due to the Earth three

    asked by Bob on December 2, 2011

More Similar Questions