Find three consecutive odd integers whose sum is less than 20 but greater than 10.
I am confused how to answer this.
I think consecutive numbers are numbers that are next to each other in sequence such as 1, 2, and 3 are consecutive numbers, if that helps any..?[:
3 5 7 are odd and consecutive-- they add to 15 which is greater than 10 and less than 20.
Thank you both so much :)
To find three consecutive odd integers whose sum is less than 20 but greater than 10, we need to follow these steps:
1. Start by assuming the first consecutive odd integer as 'x'.
2. Since the next two consecutive odd integers would be 'x + 2' and 'x + 4'.
3. Formulate the equation for their sum: x + (x + 2) + (x + 4).
4. Simplify the equation: 3x + 6.
5. Now, set up the inequality: 10 < 3x + 6 < 20.
6. Subtract 6 from all sides: 4 < 3x < 14.
7. Divide all sides by 3: 4/3 < x < 14/3.
Since we are dealing with integers, let's round up or down the resulting range of x:
x could be any integer between 2 and 4 (inclusive).
Thus, the three consecutive odd integers are:
2, 2 + 2 = 4, and 2 + 4 = 6
or
3, 3 + 2 = 5, and 3 + 4 = 7
Both sets of integers satisfy the given conditions.