trying to raise a barrel using sections of pipe.The three objects are horizontal cylinders resting on level ground. The barrel has a mass of 100 kg and its diameter is 2.0m. Each pipe has a diameter of 0.50 m. What minimum horizontal force must his feet exert on the pipe to raise barrel from the ground? Neglect Friction.
To calculate the minimum horizontal force needed to raise the barrel from the ground, we need to understand the basic principles of forces and equilibrium.
First, let's consider the forces acting on the barrel. We have the weight of the barrel acting vertically downwards, which is given by the formula:
Weight = mass x gravity
The mass of the barrel is given as 100 kg, and the acceleration due to gravity is approximately 9.8 m/s². So the weight of the barrel is:
Weight = 100 kg x 9.8 m/s² = 980 N
Now, let's visualize the situation. We have three pipes supporting the barrel, so we can imagine each pipe as a separate force pushing upwards. Therefore, the total upward force exerted by the three pipes is:
Upward force = 3 x Force exerted by one pipe
To keep the barrel in equilibrium, the upward force exerted by the three pipes should be equal to the weight of the barrel. Therefore, we can equate these two forces:
3 x Force exerted by one pipe = Weight
Now we can solve for the force exerted by one pipe:
Force exerted by one pipe = Weight / 3
Substituting the value of the weight:
Force exerted by one pipe = 980 N / 3
Calculating this, we get:
Force exerted by one pipe ≈ 327 N
So the minimum horizontal force that must be exerted on the pipe to raise the barrel from the ground is approximately 327 N.