So if i want to write the conjugate base for NH3,
NH3 <--> NH2 + H(+)
Yes, and the conjugate base is NH2^-(I don't see a negative sign on your post).
NaNH2 (sodamide) is such a compound; it gives the NH2^- ion.
To write the conjugate base of NH3, you need to remove a proton (H+) from NH3. Here's how you can get the answer:
1. Start with NH3: This is the chemical formula for ammonia, which is a weak base. It consists of one nitrogen atom (N) bonded to three hydrogen atoms (H).
2. Remove a proton (H+): In order to form the conjugate base, NH2-, you need to remove a proton from NH3. This is represented by the equilibrium arrow (<-->).
3. Write the conjugate base: After removing the proton, you are left with NH2-, which is the conjugate base of NH3. The minus sign (-) indicates that it has gained a negative charge by accepting the proton.
So, the conjugate base of NH3 is NH2-.