A particle starts from the origin at t = 0 with an initial velocity of 5.5 m/s along the positive x axis.If the acceleration is (-2.8i + 4.1jm/s^2, determine (a)the velocity and (b)position of the particle at the moment it reaches its maximum x coordinate.

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  1. The i term is the x-axis comonent and the j term is the y-axis component

    Maximum x coordinate is reached when 5.5 m/s = 2.8 t
    t = 1.9643 s

    (a) At that time, velocity is
    5.5i + (-2.8i + 4.1j)t = 4.1j*1.9643
    = 8.0536j m/s (parallel to y axis)

    (b) Position =
    0 + (5.5 t -1.4 t^2)i + 2.05 t^2 j
    Substitute 1.9643 s for t

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