What is the concentration, mass/vol percent (m/v) of a solution prepared from 50.gNaCl and 2.5L?
Do I divide 50.g NaCl/2.5L?? = 20%
Thank you!
I got this one I think
50.g/2500mL x 100%
=.02 X 100%
= 2.0 %
I agree.
To calculate the concentration, mass/volume percent (m/v) of a solution, you need to divide the mass of the solute (NaCl) by the volume of the solution and then multiply by 100.
In this case, the mass of NaCl is 50 g and the volume of the solution is 2.5 L.
Concentration = (mass of solute / volume of solution) * 100
Concentration = (50 g / 2.5 L) * 100 = 20 g/L
So, the concentration, mass/volume percent (m/v) of the solution prepared from 50 g NaCl and 2.5 L is 20 g/L.
To calculate the mass/volume percent (m/v) concentration of a solution, you need to divide the mass of the solute by the volume of the solution and then multiply by 100.
In this case, you have 50 g of NaCl (solute) and a final volume of 2.5 L (solution). To calculate the m/v percent concentration, you would divide the mass of NaCl by the volume of the solution and multiply by 100:
(mass of NaCl / volume of solution) x 100
Plugging in the values:
(50 g NaCl / 2.5 L solution) x 100 = (20 g/L) x 100 = 2000 g/L
Therefore, the concentration of the solution prepared from 50 g of NaCl and 2.5 L is 2000 g/L.
So, no, the concentration is not 20%. It is 2000 g/L.