# physics

The force required to stretch a Hooke’s-law
spring varies from 0 N to 62.4 N as we stretch
the spring by moving one end 17.2 cm from
its unstressed position.
a) Find the force constant of the spring.

b) Find the work done in stretching the spring.

1. a) 62.4 N/0.172 m = 362.8 N/m

b) (1/2)*(max stretch)(max force)
= 0.5*0.172 m*62.4 N = ___ J

posted by drwls
2. thank you for the help!!!

posted by phys101!

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