physics

The force required to stretch a Hooke’s-law
spring varies from 0 N to 62.4 N as we stretch
the spring by moving one end 17.2 cm from
its unstressed position.
a) Find the force constant of the spring.
Answer in units of N/m

b) Find the work done in stretching the spring.
Answer in units of J

asked by phys101!
  1. a) 62.4 N/0.172 m = 362.8 N/m

    b) (1/2)*(max stretch)(max force)
    = 0.5*0.172 m*62.4 N = ___ J

    posted by drwls
  2. thank you for the help!!!

    posted by phys101!

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