If 9.20 g of sodium metal reacts with chlorine gas to make sodium chloride, how mnay grams of chlorine are required to react completely with the sodium?
14.18 grams Cl2
To determine the number of grams of chlorine required to react completely with sodium, we need to use the balanced chemical equation for the reaction.
The balanced chemical equation for the reaction between sodium metal (Na) and chlorine gas (Cl2) to form sodium chloride (NaCl) is:
2 Na + Cl2 → 2 NaCl
From the balanced equation, we can see that 2 moles of sodium react with 1 mole of chlorine to produce 2 moles of sodium chloride.
To find the molar mass of sodium chloride, we need to add up the atomic masses of sodium (Na) and chlorine (Cl). The atomic masses are:
Sodium (Na): 22.99 g/mol
Chlorine (Cl): 35.45 g/mol
The molar mass of sodium chloride (NaCl) is:
22.99 g/mol (Na) + 35.45 g/mol (Cl) = 58.44 g/mol (NaCl)
Since 1 mole of sodium chloride has a molar mass of 58.44 g/mol, we can use the molar ratio from the balanced equation to calculate the grams of chlorine required.
Given that we have 9.20 g of sodium, we can calculate the amount of chlorine required as follows:
(9.20 g Na) x (1 mol NaCl / 2 mol Na) x (1 mol Cl2 / 1 mol NaCl) x (35.45 g Cl2 / 1 mol Cl2)
Multiplying these values, we find:
(9.20 g Na) x (1 / 2) x (1 / 1) x (35.45 g Cl2) = 160.426 g Cl2
Therefore, approximately 160.43 grams of chlorine are required to react completely with 9.20 grams of sodium.
To determine the number of grams of chlorine required to react completely with sodium, we need to use the balanced chemical equation for the reaction between sodium and chlorine.
The balanced equation is:
2 Na + Cl2 → 2 NaCl
According to the balanced equation, 2 moles of sodium react with 1 mole of chlorine to produce 2 moles of sodium chloride.
First, we need to calculate the number of moles of sodium based on the given mass of sodium.
To do that, we'll use the molar mass of sodium, which is 22.99 g/mol.
Number of moles of sodium = mass of sodium / molar mass of sodium
Number of moles of sodium = 9.20 g / 22.99 g/mol
Next, we can use the mole ratio from the balanced equation to determine the number of moles of chlorine required to react completely with the sodium. According to the balanced equation, 2 moles of sodium react with 1 mole of chlorine.
Number of moles of chlorine = (Number of moles of sodium) / 2
Finally, we can calculate the mass of chlorine required using the number of moles of chlorine and the molar mass of chlorine, which is 35.45 g/mol.
Mass of chlorine = number of moles of chlorine × molar mass of chlorine
Now we can substitute the values into the equation to find the answer.
Mass of chlorine = ((9.20 g / 22.99 g/mol) / 2) × 35.45 g/mol
By calculating the expression, you will find the grams of chlorine required to react completely with the sodium.