a ball is rolled up q constant slope with an initial velocity of 2.2m/s after 2 seconds the ball is rolling down the slope with a velocity of 1.1 m/s what is the acceleration of the ball
To calculate the acceleration of the ball, we can use the kinematic equation:
v = u + at
Where:
v = final velocity
u = initial velocity
a = acceleration
t = time
Given that the initial velocity (u) is 2.2 m/s, the final velocity (v) is 1.1 m/s, and the time (t) is 2 seconds, we can rearrange the equation to solve for acceleration (a).
a = (v - u) / t
Substituting the given values:
a = (1.1 m/s - 2.2 m/s) / 2 s
a = (-1.1 m/s) / 2 s
Simplifying this equation:
a = -0.55 m/s²
Therefore, the acceleration of the ball is -0.55 m/s². The negative sign indicates that the ball is decelerating, or slowing down.