Soybean meal is 12%protein corn meal is 6% proteinhowmany pounds of each should be mixed together in order to get 240pounds mixture that is 11%protein?
Ok I think I haave 200pounds of soymeal and 40 pounds of corn meal
s=240-c.12s=.06c=11*240
28.8-.12c+.06c=26.4
-.06c=-.2.4
c=40
240=40+s
s=200
Correct?
amount of 12% corn meal -- x pounds
amount of 6% corn meal --- 240-x
solve :
.12x + .06(240-x) = .11(240)
times 100
12x + 6(240-x) = 11(240)
12x + 1440 - 6x = 2640
6x = 1200
x = 200
200 pounds of the 12% stuff and
40 pound of the 6% stuff
yeh I did it!!!
To solve this problem, we need to set up a system of equations based on the given information.
Let's denote:
x = the number of pounds of soybean meal
y = the number of pounds of corn meal
We know that the total weight of the mixture should be 240 pounds, so we can write the equation:
x + y = 240
We also know that the percentage of protein in the soybean meal is 12% and in corn meal is 6%, and we want the final mixture to have 11% protein. We can use this information to set up another equation.
The protein content in soybean meal can be calculated as 12% of the weight (0.12x) and in corn meal as 6% of the weight (0.06y). The protein content in the final mixture can be calculated as 11% of the total weight (0.11 * 240 = 26.4).
So we have the second equation:
0.12x + 0.06y = 26.4
Now we have a system of equations:
x + y = 240
0.12x + 0.06y = 26.4
To solve this system of equations, we can use the method of substitution or elimination.
Let's use the substitution method. Solve the first equation for y:
y = 240 - x
Now substitute this value of y into the second equation:
0.12x + 0.06(240 - x) = 26.4
Simplifying the equation:
0.12x + 14.4 - 0.06x = 26.4
0.06x = 12
x = 200
Substitute the value of x back into the first equation to find y:
200 + y = 240
y = 40
Therefore, you should mix 200 pounds of soybean meal with 40 pounds of corn meal to get a 240-pound mixture that is 11% protein.