Chem 112

An equilibrium was established after 0.100 mol of hydrogen gas and 0.100mol of iodine gas were added to an empty 1.00L reaction vessel and heated to 700K. The color intensity of the mixture changed from deep purple to a lighter purple color. At equilibrium, concentration of iodine was 0.0213 mol/L.

Calculate the equilibrium concentrations of hydrogen gas and hydrogen iodide gas as well as Kc.

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asked by Dominique
  1. Start with an equation

    H2 + I2 -> 2HI

    so 2 moles of HI formed for each mole of I2 used.

    at start

    0.100 M/L (H2) and 0.100 M/L (I2)

    at equilibrium

    0.0213 M/L (I2) so 0.0787 M/L I2 used

    so 0.1574 M/L HI formed

    and 0.0213 M/L equlibrium concentration of H2


    Kc=[HI]^2/[H2][I2]

    plug in the values and find Kc

    Note that this Kc has no units.

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    posted by Dr Russ

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