Problem 22.2
2*10^ 13 electrons flow through a transistor in 1.0 ms.
Part A -
What is the current through the transistor?
Express your answer using two significant figures.
in mA
To find the current through the transistor, we can use the formula:
Current (I) = Number of electrons (n) / Time (t)
Given:
Number of electrons (n) = 2 * 10^13 electrons
Time (t) = 1.0 ms = 1.0 * 10^-3 s
Substituting these values into the formula, we get:
Current (I) = (2 * 10^13 electrons) / (1.0 * 10^-3 s)
To simplify the calculation, we can divide the numerator and denominator by 10^3:
Current (I) = (2 * 10^10 electrons) / (1.0 * 10^0 s)
Now, we have the current in units of electrons per second (C/s). To convert this to milliamperes (mA), we need to use the fact that 1 ampere (A) is equal to 10^3 milliamperes (mA):
1 A = 10^3 mA
So, the current in mA is:
Current (I) = (2 * 10^10 electrons / s) * (1 A / 10^3 mA)
Simplifying further, we get:
Current (I) = 2 * 10^7 mA
Therefore, the current through the transistor is 2 * 10^7 mA, expressed using two significant figures.