(k+3)^2=(2k-1)^2=0
Please help me solve this equation or maybe one like it......I keep doing it wrong.
6p^2(p+1)=4(p+1)-5p(p+1)
I also keep doing this problem wrong. I have the answer but I don't understand how its done. Please help!!
Hint.
Each term on both sides has a factor (p+1). Divide all terms on both sides by (p+1). This will simplify it for you.
Also, because of the (p+1) term remember that p=-1 will be a solution.
Okay...
Now I got 6p^2=4-5p(p+1)
I got it now....Thanks!!
the answer is (-4/3,-1,1/2)
What about the first question??? Please help me with that one...
I don't think you copied the first question correctly. Did you intend 2 equal signs?
I copied it wrong....
(k+3)^2=(2k-1)^2 .....Is the problem.
square both sides, collect like terms and solve.
Here's the first step:
(k+3)^2 = (2k-1)^2
k^2 + 6k + 9 = 4k^2 - 4k + 1
Combine all the like terms. You might factor it out, but I would suggest using the quadratic equation.