when this 3-digit number is rounded to the nearest ten, the sum of its digits is 16 .the hundreds digit of this number is 8 and the ones digit is 5 . what is the number?
if the one is 5 and the hundreds is 8, then it is 5._8, and 5 + 8 + _ = 16, so you subtract 5+8 from 16 and get 3, so the number is 5.38
8 __ 5
Rounded to the nearest ten, it's 8 __ 0
8 + 0 + x = 16
x must be 8.
880 = 8 + 8 + 0 = 16
Cody -- I don't think you read the problem correctly.
Did you forget to round the number to the nearest 10?
-_- fail. i just failed a 3rd grade math problem and i live at the illinois math and science academy. that is just sad
We all make mistakes, Cody. One of the most intelligent math and physics teachers I know recently told me that he can't add a column of numbers.
Use the digits. 3,7,1,5 to write a number that rounds to each of the following
To find the 3-digit number, let's break down the given information:
1. The hundreds digit of this number is 8.
2. The ones digit of this number is 5.
3. When the number is rounded to the nearest ten, the sum of its digits is 16.
Let's use a systematic approach to solve this problem:
Step 1: Begin by considering the number as 8 _ 5.
Step 2: Since the ones digit is 5, the number after rounding will be either 80 or 90, as these are the nearest tens.
Step 3: Now let's calculate the sum of the digits for each possibility:
a) For the number 80, the sum of its digits is 8 + 0 = 8.
b) For the number 90, the sum of its digits is 9 + 0 = 9.
Since neither of these sums match the given condition (sum of digits equaling 16), we need to reconsider the possibilities.
Step 4: Let's try adding 1 to the tens digit (which is currently empty), making it 8 1 5.
Step 5: Now, rounding this number to the nearest ten, the possible values are 80 and 90.
Step 6: Calculate the sum of the digits for each possibility:
a) For the number 80, the sum of its digits is 8 + 0 = 8.
b) For the number 90, the sum of its digits is 9 + 0 = 9.
Again, none of these options satisfy the condition.
Step 7: Finally, let's try adding 2 to the tens digit, making it 8 2 5.
Step 8: Rounding this number to the nearest ten, the possible values are 80 and 90.
Step 9: Calculate the sum of the digits for each possibility:
a) For the number 80, the sum of its digits is 8 + 0 = 8.
b) For the number 90, the sum of its digits is 9 + 0 = 9.
None of the above options match the given condition (sum of digits = 16).
After this systematic approach, we find that there is no 3-digit number where the sum of its digits is 16 after rounding to the nearest ten, given that the hundreds digit is 8 and the ones digit is 5.