an object initially at rest accelerates uniformly at 5m/sec^2 until it obtains a speed of 30m/sec. What distance does the object move while accelerating?
yes
To find the distance the object moves while accelerating, you can use one of the three equations of motion:
1. v = u + at
2. s = ut + (1/2)at^2
3. v^2 = u^2 + 2as
In this case, our initial velocity (u) is 0 m/sec since the object starts at rest. The acceleration (a) is given as 5 m/sec^2, and the final velocity (v) is 30 m/sec. We need to find the distance (s) the object moves while accelerating.
Using the equation v = u + at and substituting the given values, we can find the time (t) it takes for the object to reach the final velocity:
30 = 0 + 5t
t = 30/5
t = 6 seconds
Now we can use the equation s = ut + (1/2)at^2 to find the distance:
s = (0 * 6) + (0.5 * 5 * 6^2)
s = 0 + (0.5 * 5 * 36)
s = 0 + 90
s = 90 meters
Therefore, the object moves a distance of 90 meters while accelerating.