What is the maximum mass of S8 that can be produced by combining 92.0g of reactant?
8SO2 + 16H2S -> 2S8 + 16H2O
Which reactant?
Here is a worked example of a stoichiometry problem.
http://www.jiskha.com/science/chemistry/stoichiometry.html
89.7
To calculate the maximum mass of S8 that can be produced, we need to determine the limiting reactant. The limiting reactant is the reactant that is completely consumed first and determines the maximum amount of product that can be formed.
1. Calculate the molar masses:
- Molar mass of S8 = 8 x (atomic mass of sulfur)
- Molar mass of SO2 = atomic mass of sulfur + 2 x (atomic mass of oxygen)
- Molar mass of H2S = 2 x (atomic mass of hydrogen) + atomic mass of sulfur
- Molar mass of H2O = 2 x (atomic mass of hydrogen) + atomic mass of oxygen
2. Convert the given mass of the reactant (92.0g) to moles:
- Moles of reactant = mass of reactant / molar mass of reactant
3. Use the stoichiometric coefficients in the balanced equation to determine the mole ratio between the reactant and the product.
4. Identify the limiting reactant:
- Compare the moles of each reactant to the stoichiometric ratio. The reactant with fewer moles than predicted by the stoichiometric ratio is the limiting reactant.
5. Calculate the maximum moles of product formed using the limiting reactant.
6. Convert the moles of product to grams using the molar mass of S8.
Following these steps, you should be able to determine the maximum mass of S8 that can be produced by combining 92.0g of the reactant.