How many grams of sodium were isolated from the decomposition of 0.0292 moles of Na2O, if the reaction occurred with a 44.9% percent yeild?
2 Na2O(s) --> 4 Na(s) + O2(g)
To calculate the grams of sodium isolated from the decomposition of 0.0292 moles of Na2O, we need to follow a few steps:
Step 1: Determine the molar mass of Na2O.
The molar mass of Na2O can be calculated by adding up the atomic masses of sodium (Na) and oxygen (O). The atomic mass of Na is 22.99 g/mol, and the atomic mass of O is 16.00 g/mol.
Molar mass of Na2O = (2 x atomic mass of Na) + atomic mass of O
= (2 x 22.99 g/mol) + 16.00 g/mol
= 45.98 g/mol + 16.00 g/mol
= 61.98 g/mol
Step 2: Calculate the moles of Na produced from the moles of Na2O.
According to the balanced chemical equation:
2 Na2O(s) --> 4 Na(s) + O2(g)
The stoichiometry ratio between Na2O and Na is 2:4 (or 1:2). This means for every 2 moles of Na2O decomposed, 4 moles of Na are produced. Therefore, we can calculate the moles of Na produced from the moles of Na2O as follows:
Moles of Na = (moles of Na2O) x (4 moles of Na / 2 moles of Na2O)
= 0.0292 moles x (4 / 2)
= 0.0292 moles x 2
= 0.0584 moles
Step 3: Calculate the actual yield of sodium.
The question states that the reaction occurred with a 44.9% yield. This means that only 44.9% of the theoretically predicted amount of sodium was obtained.
Actual yield of Na = (percent yield / 100) x (theoretical yield of Na)
= (44.9 / 100) x (0.0584 moles)
= 0.449 x 0.0584 moles
= 0.0262 moles
Step 4: Convert moles to grams.
To convert moles of sodium to grams, we need to multiply the moles by the molar mass of sodium (22.99 g/mol).
Grams of Na = (moles of Na) x (molar mass of Na)
= 0.0262 moles x 22.99 g/mol
= 0.601 g
Therefore, approximately 0.601 grams of sodium were isolated from the decomposition of 0.0292 moles of Na2O, considering a 44.9% yield.