# algebra

write each problem in form ax^p +bx^q p and q are rational numbers

[x^2-4x^(1/2)]/2x^(1/3)

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1. but i don't know how to get there

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2. separate into two fractions

= x^2 /(2x^1/3)) - 4x^(1/2) / (2x^(1/2))
remember in dividing powers, we keep the base and subtract the exponents

= x^(5/3) / 2 - 2^(1/6)
= (1/2)x^*5/3) + 2x^(1/6)

(2 - 1/3 = 6/3-1/3 = 5/3
and
1/2 - 1/3 = 3/6 - 2/6 = 1/6 )

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3. fourth line should say

= x^(5/3) / 2 - 2x^(1/6)

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