physics 180

a gazelle attempts to leap a 1.8 meter fence. assuming a 45 degree takeoff angle, what's the minimum speed for the jump?

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  1. recall that for a projectile motion, the maximum height that the object can reach is given by the formula,
    h,max = [(vo)^2 * sin^2 (θ)]/(2g)
    where
    vo = initial velocity
    θ = angle of release
    g = acceleration due to gravity = 9.8 m/s^2
    the unknown in the problem is vo. thus we just substitute the given in the formula:
    h,max = [(vo)^2 * sin^2 (θ)]/(2g)
    1.8 = [(vo)^2 * sin^2 (45)]/(2*9.8)
    1.8*2*9.8 = (vo)^2 * (1/2)
    34.2 = (vo)^2 * (1/2)
    70.56 = (vo)^2
    vo = sqrt(70.56)
    vo = 8.4 m/s

    hope this helps~ :)

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