# trig

tan ø = 5; Quad I

How do I find the other 5 function values?

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1. since tanØ = opposite/adjacent or y/x
it is simple to draw a right angled triangle in the first quadrant where the base is 1 and the height is 5, making the hypotenuse √26

Now it is easy .....

sinØ = 5√26 , cscØ = √26/5
cosØ = 1/√26 , secØ = √26
tanØ = 5 , cotØ = 1/5

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