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algebra
solve the following equation by clearing fractions show all work want to know if this right 7/35/2x=8+2x 6(2/3)(5/2x)(6)=6(8)+2x(6) 14x15=48+12x 14x12x15=48+14x14x 2x15=48 2x15+15=48+14x14x 2x15=48 2x15+15=48+15
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how do i do x2+12x+32 x2+12x = 14x+32 subtract 14x from each side 14x=32 divide by 2 7x=16 x=16/7, which is 2 and 2/7 ok maybe you typed that question wrong? is it x^2 + 12x + 32 ? if it is then the solution is: (x+8)(x+4) because
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