A helicopter is ascending (moving upwards) at a constant velocity of 8 m/s. At a height of 90m, a passenger opens a window and drops a package to the ground below. How long does it take the package to hit the ground and how fast is it moving just before impact?

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  1. d = Vo*t + 0.5gt^2 = 90m,
    0 + 0.5*9.8*t^2 = 90,
    4.9t^2 = 90,
    t^2 = 18.36,
    t = 4.29s.

    Vf = Vo + gt,
    Vf = 0 + 9.8*4.29 = 42m/s.

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