A ball is thrown off a cliff from a ht of 180 ft above sea level. The ht s of the ball above sea water level at time t is s(t)=-16t2+32t+180. When will the ball strike the water?

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  1. When the ball strikes the water, the ht above water will be 0.

    h = -16t^2 +32t + 180 = 0,
    Solve for t using the Quadratic Formula
    and get:
    t = -2.5, and 4.5s.
    Select the positive value t:
    t = 4.5s.

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