Chemistry

Calculate the pH of the resulting solution if 21.0 mL of 0.210 M HCl(aq) is added to
a) 26.0 mL of 0.210 M NaOH(aq)
b) 31.0 mL of 0.260 M NaOH(aq)

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  1. moles HCl = M x L = ??
    moles NaOH = M x L = ??
    Which is in excess.
    delta moles = (H^+) or (OH^-) depending upon which in in excess, then
    M = moles/total volume in L.
    Finally, pH = =log(H^+) or pOH= -log(OH^-)

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  2. 13.56

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