algebra

how would you solve:
Find the sum of the first 12 terms to the earest hundreth 6 + 2 + 2/3 +...

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  1. looks like a geometric series with
    a = 6 , r = 1/3

    sum12 = 6((1/3)^12 - 1)/(1/3 - 1)
    = 6(1/531441 - 1)/(-2/3)
    = 8.999983

    = 9.00 correct to the nearest hundredth

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