Algebra
can you solve this set of equations using the elimination method?
3x+4y=34 and 3x+2y=26
asked by
Shirley

3x+4y=34
3x+2y=26
(1)3X+4Y=34
(1)3X+2Y=26
3X+4Y=34
3X+(2Y)=26
6Y=60
Y=10
3X+2(10)=26
3X+20=26
3X=2620
3X=6
X=2
posted by Anonymous

???
4y2y=3426posted by Mgraph
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