A 0.15 kg ball is attached to the end of a 0.82 m string and moved in a horizontal circle at 4.3 m/s what net force is needed to keep it in a circular path
To determine the net force needed to keep the ball in a circular path, we can use the centripetal force equation:
F = (m * v^2) / r
Where:
F = net force (in Newtons)
m = mass of the ball (in kilograms)
v = velocity of the ball (in meters per second)
r = radius of the circular path (in meters)
In this case, the mass of the ball is given as 0.15 kg, the velocity is 4.3 m/s, and the radius can be found using the length of the string, which is 0.82 m.
So, the first step is to calculate the radius:
r = length of string = 0.82 m
Next, we can substitute these values into the formula:
F = (0.15 kg * (4.3 m/s)^2) / 0.82 m
Now, let's calculate the centripetal force:
F = (0.15 * 18.49) / 0.82
F ≈ 3.37 N
Therefore, the net force needed to keep the ball in a circular path is approximately 3.37 Newtons.