physics

Determine the stopping distances for a car with an initial speed of 93 km/h and human reaction time of 3.0 s for the following accelerations:
-4.00 m/s^2
-8.00 m/s^2

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asked by Phil
  1. Vo = 93 km/h = 25.8 m/s

    Lat a be the acceleration.

    Distance travelled during reaction time = 25.8 * (reaction time)
    Distance travelled while decelerating = Vo^2/(2|a|)
    Add the times.

    Anyone with a reaction time of 3.0 seconds should not be driving. Recheck the numbers in the problem.

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    posted by drwls

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